12^3-20x^2+x+3=0

Solution for 12^3-20x^2+x+3=0 equation:

12^3-20x^2+x+3=0

We add all the numbers together, and all the variables

-20x^2+x+1731=0

a = -20; b = 1; c = +1731;
Δ = b2-4ac
Δ = 12-4·(-20)·1731
Δ = 138481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{138481}}{2*-20}=\frac{-1-\sqrt{138481}}{-40}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{138481}}{2*-20}=\frac{-1+\sqrt{138481}}{-40}
$